Intermediate Algebra: Solve (2m-1)^2 = -25 in simplest form

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Helen

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Oct 28, 2007
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Solve the equation. Express radicals in simplest form.
This is the problem: (2m - 1)^(2) = -25
This is my answer: {1 + 5i, 1 - 5i} over 2 2
It is hard to put on paper, hope you can figure it out.
Is my answer correct?
 
Re: Intermediate Algebra

I got \(\displaystyle m=\frac{1\pm 5i}{2}\)

I think that is what you have indicated.

I goofed the first time.
 
Helen said:
Solve the equation. Express radicals in simplest form.
This is the problem: (2m - 1)^(2) = -25
This is my answer: {1 + 5i, 1 - 5i} over 2 2
It is hard to put on paper, hope you can figure it out.
Is my answer correct?
Click to expand...
\(\displaystyle (2m -1)^2 = - 25\)

\(\displaystyle 2m -1 = \sqrt{- 25}\)

\(\displaystyle 2m -1 = \pm 5i\)

\(\displaystyle 2m = 1 \pm 5i\)

\(\displaystyle m = \frac{1 \pm 5i}{2}\)

Your answers were correct
 
Re: Intermediate Algebra

Loren said:
I got \(\displaystyle m=\frac{1\pm i\sqrt{5}}{2}\) <-- small typo \(\displaystyle \sqrt{}\) should not be there
I think that is what you have indicated.
Click to expand...
 
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