intermediate aglebra

NAPALADY

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Joined
Mar 14, 2010
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1
How do I get the answer for launching a rocket. The height is 70 and the time is 3 seconds so how many feet will it go in the air?
h+vt-4.9t^2
70 +vt-4.9t^2
70+30-4.9t^2
70+30(3)-4.9(3)^2 This is the line I have trouble with on figure it out..
is it 70+30Times 3 .so do I times the 70 with it or just the 30? minus 4.9. again the (3)^2?
 
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