tapout1829
New member
- Joined
- Mar 20, 2006
- Messages
- 6
center of gravity...
y= (-2x^2 / 169) + (4x / 13) + 3 (0<x<26 < = less that or equal to)
actual distance the center of gravity travels is approx. 26.4046
evaluate the definite integral by first using the subsitution --> tan u = (-4 / 169)x + (4 / 13) and then integrate sec^3u
Thanks guys ..yous are much help
y= (-2x^2 / 169) + (4x / 13) + 3 (0<x<26 < = less that or equal to)
actual distance the center of gravity travels is approx. 26.4046
evaluate the definite integral by first using the subsitution --> tan u = (-4 / 169)x + (4 / 13) and then integrate sec^3u
Thanks guys ..yous are much help