intergrate: e^(sin theta) cos theta

[dangerous_dave]

How can I intergrate: e^(sin theta) cos theta

Thanks forany help.

 

[o_O]

\(\displaystyle \int e^{\sin \theta} \: \cos \theta d\theta\)

\(\displaystyle u = \sin \theta\)
\(\displaystyle du = \cos \theta d\theta\)

Making the subs:
\(\displaystyle \int e^{\overbrace{\sin \theta}^{u}} \overbrace{\cos \theta d\theta}^{du}\)

 

[dangerous_dave]

Are you saying that, when integrated, its the same as before?

 

[skeeter]

that's not what o_0 said ...

\(\displaystyle \int e^{\sin{\theta}} \cos{\theta} \, d \theta = e^{\sin{\theta}} + C\)