Intergral Help 2

[nil101]

Please can you check if I have applied the right technique to this intergral?

\(\displaystyle \L \int_0^1 {\frac{x}{{4 - x^2 }}}\,dx\)


\(\displaystyle \L = - \frac{1}{2}\int {\frac{{ - 2x}}{{4 - x^2 }}}\,dx\)

\(\displaystyle \L = - \frac{1}{2}\ln \left| {4 - x^2 } \right| + K\)

Thanks

_{Edit TKHunny: Don't forget your "dx".}

 

[stapel]

Differentiate your answer. Do you get your original integrand? If so, then you're "good to go"!

Eliz.

 

[tkhunny]

Didn't your definite integral turn indefinite?