integration with inverse trig. functions~please help

[roxstar1]

/ = integral sign

/ ((4x+3)/(1-x^2)^1/2) dx


so far, I have separated this into two equations:

/ ((4x)/(1-x^2)^1/2) dx + 3 / ((1)/ (1-x^2)^1/2) dx

? + 3arcsin(x) + C

I'm not sure how to integrate the first part of the integral. Could someone let me know if im right so far and how to integrate the first part?

 

[Daniel_Feldman]

For the first part, take 4 out of the integral and let u=1-x^2.

 

[roxstar1]

thankyou, i think i may have figured it out now