Integration question.

SteveB

New member
Joined
Jan 18, 2010
Messages
2
Goog morning:

I am trying to integrate to following problem:

4-X^2
4-2x dx.....the limits of integration are zero to one

I'm not sure how to get the x out of the denominator

One way I've tried doing it is to mutiply the numerator by 4- 2x giving my a large polynomial...but when I integrate this I don't get the correct answer which is 5/4.


I think I may need to substitute but this fraction in the denominator has me stuck...

Any hints would be appreciated.

thanks.
 
Just factor:

\(\displaystyle \int_{0}^{1}\frac{4-x^{2}}{4-2x}dx=\int_{0}^{1}\left[\frac{(2-x)(x+2)}{2(2-x)}\right]dx\)
 
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