mickeymouse
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- Joined
- Jan 2, 2009
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If int { -1 to 3} f(x+k) dx= 8, where k is a constant, then int {(k-1) to (k+3)} f(x) dx= ???
I'm not sure how to approach this...
I'm not sure how to approach this...
mickeymouse said:If int { -1 to 3} f(x+k) dx= 8, where k is a constant, then int {(k-1) to (k+3)} f(x) dx= ???
I'm not sure how to approach this...
Consider the graph of f(x) from k−1 to k+3.If ∫-13f(x+k)dx=8, where k is a constant, find: ∫k−1k+3f(x)dx
|
| * *
| :::* *:
| ::::::*::::
| :::::::::::
- - + - - * - - - - * - -
| k-1 k+3
|
* | *
::|* *:
::|:::*::::
::|::::::::
- * + - - - * - - - -
-1 | 3