Hello there,
I'm attempting to solve int(t sin 2t dt) by parts instead of using u-substitution, by I stumbled upon the wrong answer, and I can't figure out what's my mistake.
Here's how it goes:
int(t sin 2t dt) =
= (-1/2)int[t*d(cos2t)] =
= (-1/2)[t*cos2t + int(cos2t*dt)] =
= (-1/2)t*cos2t - (1/2)int(cos2t*dt)=
= (-1/2)*t*cos2t - (1/4)sin2t.
The correct answer is (-1/2)*t*cos2t + (1/4)sin2t, but I can't seem to find the (-1) that would set my answer right.
ps.: I wanna solve it without any sort of substitution.
I'm attempting to solve int(t sin 2t dt) by parts instead of using u-substitution, by I stumbled upon the wrong answer, and I can't figure out what's my mistake.
Here's how it goes:
int(t sin 2t dt) =
= (-1/2)int[t*d(cos2t)] =
= (-1/2)[t*cos2t + int(cos2t*dt)] =
= (-1/2)t*cos2t - (1/2)int(cos2t*dt)=
= (-1/2)*t*cos2t - (1/4)sin2t.
The correct answer is (-1/2)*t*cos2t + (1/4)sin2t, but I can't seem to find the (-1) that would set my answer right.
ps.: I wanna solve it without any sort of substitution.
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