Integrate trig functions: integrate cos^2 (x)

[greese]

Integrate cos^2 (x)

I have: [sin^3 (x) cos^3 (x) ] / [3 sin^2 (x) cos (x)]

But truly i am stuck

 

[Deleted member 4993]

Re: Integrate trig functions

Integrate cos^2 (x)

I have: [sin^3 (x) cos^3 (x) ] / [3 sin^2 (x) cos (x)]<<< Incorrect

But truly i am stuck

Hint:

$\displaystyle \cos(2\theta) \, = \, 2\cos^2(\theta) \, - \, 1$

 

[fasteddie65]

Re: Integrate trig functions

Integrate cos^2 (x)

I have: [sin^3 (x) cos^3 (x) ] / [3 sin^2 (x) cos (x)]<<< Incorrect

But truly i am stuck

Hint:

$\displaystyle \cos(2\theta) \, = \, 2\cos^2(\theta) \, - \, 1$

So cos^2 x = (1 + 2 cos 2x)/2

That should be easy to integrate.

 

[Deleted member 4993]

Re: Integrate trig functions

Integrate cos^2 (x)

I have: [sin^3 (x) cos^3 (x) ] / [3 sin^2 (x) cos (x)]<<< Incorrect

But truly i am stuck

Hint:

$\displaystyle \cos(2\theta) \, = \, 2\cos^2(\theta) \, - \, 1$

So cos^2 x = (1 + 2 cos 2x)/2 <<< small typo - should be - >>> [sub:1g8g99u3]$\displaystyle \cos^2(x) \, = \frac{1 \, + \, \cos(2x)}{2}$[/sub:1g8g99u3]

That should be easy to integrate.