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Integrate trig functions: integrate cos^2 (x)
- Thread starter greese
- Start date
D
Deleted member 4993
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Re: Integrate trig functions
Hint:
\(\displaystyle \cos(2\theta) \, = \, 2\cos^2(\theta) \, - \, 1\)
greese said:Integrate cos^2 (x)
I have: [sin^3 (x) cos^3 (x) ] / [3 sin^2 (x) cos (x)]<<< Incorrect
But truly i am stuck
Hint:
\(\displaystyle \cos(2\theta) \, = \, 2\cos^2(\theta) \, - \, 1\)
fasteddie65
Full Member
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- Nov 1, 2008
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- 360
Re: Integrate trig functions
So cos^2 x = (1 + 2 cos 2x)/2
That should be easy to integrate.
Subhotosh Khan said:greese said:Integrate cos^2 (x)
I have: [sin^3 (x) cos^3 (x) ] / [3 sin^2 (x) cos (x)]<<< Incorrect
But truly i am stuck
Hint:
\(\displaystyle \cos(2\theta) \, = \, 2\cos^2(\theta) \, - \, 1\)
So cos^2 x = (1 + 2 cos 2x)/2
That should be easy to integrate.
D
Deleted member 4993
Guest
Re: Integrate trig functions
fasteddie65 said:Subhotosh Khan said:greese said:Integrate cos^2 (x)
I have: [sin^3 (x) cos^3 (x) ] / [3 sin^2 (x) cos (x)]<<< Incorrect
But truly i am stuck
Hint:
\(\displaystyle \cos(2\theta) \, = \, 2\cos^2(\theta) \, - \, 1\)
So cos^2 x = (1 + 2 cos 2x)/2 <<< small typo - should be - >>> [sub:1g8g99u3]\(\displaystyle \cos^2(x) \, = \frac{1 \, + \, \cos(2x)}{2}\)[/sub:1g8g99u3]
That should be easy to integrate.