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integrals
- Thread starter CalcGuy
- Start date
D
Deleted member 4993
Guest
CalcGuy said:so im in the middle of a more comlex problem but im kinda stumped on this part... it says that the integral of:
e/(u+e)
is
eln|u+e|
i dont see how they did that? i keep ending up with ln|u+e| so im an e short...
\(\displaystyle \int \frac{e^1}{u+e^1} du = e^1\int \frac{1}{u+e^1} du= e^1* ln|(u+e^1)| + C\)
so... im still not quite sure i get it? im thinking you substitute some letter say v for u+e so v=u+e so you have 1/v to integrate... but then you have dv and isnt dv=e du or something? so shouldnt that eliminate the e in the numerator? and then you wouldnt have an e to pull out in front of the intergral...
D
Deleted member 4993
Guest
CalcGuy said:so... im still not quite sure i get it? im thinking you substitute some letter say v for u+e so v=u+e so you have 1/v to integrate...
but then you have dv and isnt dv=e du or something? <<< No - e (= 2.718281828...) is a universal "constant" - like ?.
so shouldnt that eliminate the e in the numerator? and then you wouldnt have an e to pull out in front of the intergral...