To find the indefinite integral of 3e^5t, wouldn't the answer be the same (3e^5t) since the integral of an exponential function with base e is equal to the function itself?
Because the indefinite ingeral is just the anti-derivative consider this:
\(\displaystyle \L\frac{{d\left( {\frac{3}{5}e^5 } \right)}}{{dx}} = 3e^5 .\)
This site uses cookies to help personalise content, tailor your experience and to keep you logged in if you register.
By continuing to use this site, you are consenting to our use of cookies.