integral of 3 / sqrt (3- x^2 - 2x) dx

[math]

integral of 3 / sqrt (3- x^2 - 2x) dx

Do I complete the square and how if I should? How do I manipulate this into arcsin?

 

[galactus]

Expand and use partial fractions is one way.

\(\displaystyle \L\\\frac{3}{-x^{2}-2x+3}=\frac{3}{4(x+3)}-\frac{3}{4(x-1)}\)

 

[stapel]

Duplicate thread deleted.