Integral from [0, 1]: x-1/2x+3 dx
(I've tried splitting it up x/2x+3 - 1/2x+3. I know the second part is a 1/2ln(2+3) but can't figure out how to solve for the first part)
Integral from [0, 1]: x-1/2x+3 dx
(I've tried splitting it up x/2x+3 - 1/2x+3. I know the second part is a 1/2ln(2+3) but can't figure out how to solve for the first part
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