Definite Integral with top at 3 and bottom at -2
\(\displaystyle \int (x^{3} - 4x) dx \)
\(\displaystyle \rightarrow \dfrac{x^{4}}{4} - \dfrac{4x^{2}}{2}\)
\(\displaystyle \rightarrow \dfrac{x^{4}}{4} - 2x^{2}\)
\(\displaystyle [\dfrac{(3)^{4}}{4} - 2(3)^{2}] - [\dfrac{(-2^{4}}{4} - 2(-2)^{2}]\)
\(\displaystyle \dfrac{81}{4} - 18] - [-\dfrac{16}{4} - 8]\)
\(\displaystyle [\dfrac{81}{4} - 18] + [\dfrac{16}{4} - 8]\)
\(\displaystyle [\dfrac{81}{4} - \dfrac{72}{4}] + [\dfrac{16}{4} -\dfrac{32}{4}]\)
\(\displaystyle [\dfrac{9}{4}] + [-\dfrac{16}{4}\)
\(\displaystyle [\dfrac{9}{4}] - [\dfrac{16}{4}] = -\dfrac{7}{4}\) - The computer says answer is wrong.
\(\displaystyle \int (x^{3} - 4x) dx \)
\(\displaystyle \rightarrow \dfrac{x^{4}}{4} - \dfrac{4x^{2}}{2}\)
\(\displaystyle \rightarrow \dfrac{x^{4}}{4} - 2x^{2}\)
\(\displaystyle [\dfrac{(3)^{4}}{4} - 2(3)^{2}] - [\dfrac{(-2^{4}}{4} - 2(-2)^{2}]\)
\(\displaystyle \dfrac{81}{4} - 18] - [-\dfrac{16}{4} - 8]\)
\(\displaystyle [\dfrac{81}{4} - 18] + [\dfrac{16}{4} - 8]\)
\(\displaystyle [\dfrac{81}{4} - \dfrac{72}{4}] + [\dfrac{16}{4} -\dfrac{32}{4}]\)
\(\displaystyle [\dfrac{9}{4}] + [-\dfrac{16}{4}\)
\(\displaystyle [\dfrac{9}{4}] - [\dfrac{16}{4}] = -\dfrac{7}{4}\) - The computer says answer is wrong.
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