Integral: cos^2xsinx

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Please help, I have been working on this problem for ever.

Integrate cos^2xsinx over [0,pi]

I know the answer is 2/3, but I can not get it for the life of me.

Thank you!

 

[royhaas]

Use the substitution \(\displaystyle y=cos(x)\).

 

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Thank you so much! I help doing cos^2x.