Hey guys!
I'm trying to solve and I'm not getting anywhere (both my text books and the net aren't helping me very much tonight)!
y=(−7.63)[sin(9.48x)] x=-4 and x=0
Answer:
Integral Area = 0.0196 (to four decimals)
We have only just started learning Integrals (and as I didn't finish high school over 10 years ago) I'm really struggling with this topic. I understand that integration is basically the oppersite of differentiation. SO, the integral of sin is -cos (I think).
Here is what I think:
∫0−4(−7.63)[sin(9.48x)]dx
From what I have read thus far you take the (−7.63) out infront of the ∫0−4 to become:
(−7.63)∫0−4[sin(9.48x)]dx ** I just pulled that from an example I read here on this site that one of the admins did for another member**
Thanks for your time.
I'm trying to solve and I'm not getting anywhere (both my text books and the net aren't helping me very much tonight)!
y=(−7.63)[sin(9.48x)] x=-4 and x=0
Answer:
Integral Area = 0.0196 (to four decimals)
We have only just started learning Integrals (and as I didn't finish high school over 10 years ago) I'm really struggling with this topic. I understand that integration is basically the oppersite of differentiation. SO, the integral of sin is -cos (I think).
Here is what I think:
∫0−4(−7.63)[sin(9.48x)]dx
From what I have read thus far you take the (−7.63) out infront of the ∫0−4 to become:
(−7.63)∫0−4[sin(9.48x)]dx ** I just pulled that from an example I read here on this site that one of the admins did for another member**