Integral along a closed path

[Guest]

I do not understand this concept of an integral on a closed path...the question is

Evaluate the integral of the given function \(\displaystyle f(z)=2z^2+3z-1+\frac{4}{z}\), along the simple closed path \(\displaystyle |z|=4\) in its positive evaluation and locate the singularities of the function then draw the path of integration.

...do i just approach this as I would an elementary integral...but then how would the graph look? And what is a negative and/or positive evaluation?



Thanks in advance.

 

[pka]

Look at my reply to your other posting.
You must apply the Cauchy Integral Formula.
|z|=4 is a circle with center at the origin, a singularity of the integrand.