Integer

hbtcutie92

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Apr 20, 2006
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If the nymebr represented by n-3 is an odd integer, which expression represents the next greatest odd integer?

1) n-5 2) n-2 3) n-1 4) n + 1

I think its n - 1 because n -5 lower number then -3 on the negative side. n- 2 is not odd, and n+ 1 is just not right, so i think its 3) n-1
 
Correct answer, with correct reasoning.

Eliz.
 
that is the correct answer ,,to get a greater integer you have to reduce the number you are using to subtract . Since it says you need the next "ODD" integer it was -1. do you understand it now ?
 
Hello, hbtcutie92!

If the number represented by \(\displaystyle n-3\) is an odd integer,
which expression represents the next greatest odd integer?

\(\displaystyle 1)\;n\,-\,5\;\;\;2)\;n\,-\,2\;\;\;3)\;n\,-\,1\;\;\;4)\;n\,+\,1\)

I think it's \(\displaystyle n-1\) because \(\displaystyle n -5\) is lower number then \(\displaystyle n-3\) on the negative side.
\(\displaystyle n- 2\) is not odd, and \(\displaystyle n+1\) is just not right, so i think it's \(\displaystyle 3)\;n\,-\,1\)
Your reasoning and your answer are correct.
However, there is a faster and neater solution.

We know that odd numbers "go up by twos".
\(\displaystyle \;\;\)-5 + 2 = -3 . . . 7 + 2 = 9 . . . 13 + 2 = 15 . . . etc.

So if \(\displaystyle n\,-\,3\) is an odd integer,
\(\displaystyle \;\;\)the next odd integer is: \(\displaystyle \,(n\,-\,3)\,+\,2\:=\:n\,-\,1\)
 
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