integer problem: sum of squares of cons. odds is 202

[marcellla]

I am stuck on an integer problem. Not sure how to set it up

The sum of the squares of two consecutive odd numbers is equal to 202.
Find the two integers.

Please if any one knows I would appreciate the help

 

[skeeter]

let x = the first odd integer
then x+2 = the next odd integer

The sum of the squares of two consecutive odd numbers is equal to 202.

translate the problem statement into an equation ...

x² + (x+2)² = 202

solve for x.

 

[Mrspi]

Re: integer problem

I am stuck on an integer problem. Not sure how to set it up

The sum of the squares of two consecutive odd numbers is equal to 202.
Find the two integers.

Please if any one knows I would appreciate the help

Consecutive odd integers would be things like -5, -3, -1 or 11, 13, 15. Notice that each odd integer is two more than the one that comes before it.

Let x = the first odd integer
Then x + 2 = the next consecutive odd integer.

x<SUP>2</SUP> is the square of the first integer, and (x + 2)<SUP>2</SUP> is the square of the next consecutive odd integer. The sum of the squares is 202. So,

x<SUP>2</SUP> + (x + 2)<SUP>2</SUP> = 202

I hope you can solve for x now.....

 

[marcellla]

thanks for the reply

I came up with n=5 and n=10

is this correct?

 

[Deleted member 4993]

thanks for the reply

I came up with n=5 and n=10.........Are these consecutive odd numbers?

is this correct?

Look at the examples MrsPi posted for you - those are consecutive odd numbers.

How did you come up with your answer?

Can you please show your work - so that we can go through it properly?

 

[marcellla]

I now realize the previous answer was incorrect.

I worked the problem and came up with 9 and 11.

thanks for your help