int 1 / (sqrt x + ^3sqrt x ) dx (hint: let u = 6 sqrt x, and
- Thread starter crzymath
- Start date
Re: tough integration problem
This this what you mean?.:
\(\displaystyle \int\frac{1}{\sqrt{x}+\sqrt[3]{x}}dx\)
If we make the sub \(\displaystyle u=x^{\frac{1}{6}}, \;\ u^{6}=x, \;\ u^{5}du=\frac{1}{6}dx\)
Making the subs gives us:
\(\displaystyle \int\left(6u^{2}-6u+6-\frac{6}{u+1}\right)du\)
This this what you mean?.:
\(\displaystyle \int\frac{1}{\sqrt{x}+\sqrt[3]{x}}dx\)
If we make the sub \(\displaystyle u=x^{\frac{1}{6}}, \;\ u^{6}=x, \;\ u^{5}du=\frac{1}{6}dx\)
Making the subs gives us:
\(\displaystyle \int\left(6u^{2}-6u+6-\frac{6}{u+1}\right)du\)
