Inga is starting new rectangular garden. She wants the lengt

[JayJay06]

Inga is starting new rectangular garden. She wants the length to be 3 times the width, and she has 56 meters of fencing to put around the garden. Use the system of equation listed below to find the length "l" and the width "w" of the garden.
2L + 2W = 56 and L = 3w

I do not know haw to set up the problem. May some one plz help me.

I have tried but this doesn't look right to me.

2L + 2W - 3W = 56 - 3W

 

[galactus]

You're so close. Just go on.

Perimeter = 2W+2L=56...[1]

L=3W....[2]

Sub [2] into [1] and solve for W

 

[JayJay06]

2L+3w=56

2L+3w-3w= 56 - 3w/3

2L = 18.67

L= 9.335

 

[skeeter]

2L+3w=56

2L+3w-3w= 56 - 3w/3

2L = 18.67

L= 9.335

no.

L = 3W

2L + 2W = 56

2(3W) + 2W = 56

6W + 2W = 56

8W = 56

W = 7

L = 3W = 3(7) = 21

check the solution ...

P = 2L + 2W

P = 2(21) + 2(7)

P = 42 + 14 = 56