fasteddie65 said:On the first trip from B to AC, it travels a distance of 5?3.
Heading back to AB, it travels 5, then 2.5?3, then 2.5, etc.
(5 + 2.5 + 1.25 + ...) + (5 + 2.5 + 1.25 + ...)?3 =
Do you see what is needed here?
F19 said:… how you got 5 traveling back to AB. Could you please clarify?