X xc630 Junior Member Joined Sep 1, 2005 Messages 164 May 12, 2006 #1 Hi, I am having toruble with this problem: 2x >x+10> -x The answer is suppsoed to be x>10 but I do not understand how you get that answer. Thanks for your help.
Hi, I am having toruble with this problem: 2x >x+10> -x The answer is suppsoed to be x>10 but I do not understand how you get that answer. Thanks for your help.
stapel Super Moderator Staff member Joined Feb 4, 2004 Messages 16,550 May 12, 2006 #2 What are the instructions for this exercise? Thank you. Eliz.
skeeter Elite Member Joined Dec 15, 2005 Messages 3,204 May 13, 2006 #3 xc630 said: Hi, I am having toruble with this problem: 2x >x+10> -x The answer is suppsoed to be x>10 but I do not understand how you get that answer. Thanks for your help. Click to expand... look at it as two inequalities ... 2x > x + 10, and x + 10 > -x solve each one individually ... 2x > x + 10 x > 10 x + 10 > -x 2x + 10 > 0 2x > -10 x > -5 you have two solution sets ... x > 10 and x > -5 the intersection of those two sets (where they overlap) is the set x > 10 because all values of x > 10 will satisfy both inequalities.
xc630 said: Hi, I am having toruble with this problem: 2x >x+10> -x The answer is suppsoed to be x>10 but I do not understand how you get that answer. Thanks for your help. Click to expand... look at it as two inequalities ... 2x > x + 10, and x + 10 > -x solve each one individually ... 2x > x + 10 x > 10 x + 10 > -x 2x + 10 > 0 2x > -10 x > -5 you have two solution sets ... x > 10 and x > -5 the intersection of those two sets (where they overlap) is the set x > 10 because all values of x > 10 will satisfy both inequalities.