inductive resoning problems
- Thread starter gail
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mmm4444bot
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It's not easy to help people who say nothing about their situation.
Where are you stuck, on each of these? In other words, what have you tried or thought about so far? What is your math class currently working on?
Also, we prefer that you begin a new thread for each exercise's discussion. More information about posting may be found in our Forum Guidelines. Please be complete, when requesting help.
Cheers. :cool:
Where are you stuck, on each of these? In other words, what have you tried or thought about so far? What is your math class currently working on?
Also, we prefer that you begin a new thread for each exercise's discussion. More information about posting may be found in our Forum Guidelines. Please be complete, when requesting help.
Cheers. :cool:
mmm4444bot
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- Oct 6, 2005
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This exercise has a lot to do with pattern recognition.
Note the progression of the denominators: 8,7,2,5
It would be nice, if that 2 were a 6 instead. Then we'd have a clear progression: 8,7,6,5
Can you think of a way to get a 6 down there?
If so, replace the 1/2 with your rewritten ratio, and then look at the progression of the numerators. :cool:
Hello, gail!
Here are the first two . . .
We have:
. . \(\displaystyle \begin{array}{ccccc} 360\,\times\,\frac{1}{2} &=& 180 \\ 180\,\times\,\frac{2}{3} &=& 120 \\ 120 \times \frac{3}{4} &=& 90 \\ 90 \times \frac{4}{5} &=& \color{red}{72} \\ 72 \times \frac{5}{6} &=& \color{red}{60} \end{array}\)
We have:
. . \(\displaystyle \begin{array}{ccc} \frac{1}{8} \\ \frac{2}{7} \\ \frac{3}{6} &=& \frac{1}{2} \\ \frac{4}{5} \\ \color{red}{\frac{5}{4}} \\ \frac{6}{3} &=& \color{red}{2} \end{array}\)
Here are the first two . . .
We have:
. . \(\displaystyle \begin{array}{ccccc} 360\,\times\,\frac{1}{2} &=& 180 \\ 180\,\times\,\frac{2}{3} &=& 120 \\ 120 \times \frac{3}{4} &=& 90 \\ 90 \times \frac{4}{5} &=& \color{red}{72} \\ 72 \times \frac{5}{6} &=& \color{red}{60} \end{array}\)
We have:
. . \(\displaystyle \begin{array}{ccc} \frac{1}{8} \\ \frac{2}{7} \\ \frac{3}{6} &=& \frac{1}{2} \\ \frac{4}{5} \\ \color{red}{\frac{5}{4}} \\ \frac{6}{3} &=& \color{red}{2} \end{array}\)