Hello, jen1990!
You're almost there . . .
You <u>assumed</u> that triangle RST is not isosceles.
Then we are given: \(\displaystyle RU=RU\) and \(\displaystyle \angle RUS\,=\,\angle RUT\) and \(\displaystyle \angle SRU\,=\,\angle TRU\)
Then: \(\displaystyle \Delta RUS\) is congruent to \(\displaystyle \Delta RUT\) by a.s.a.
Hence: \(\displaystyle RS\,=\,RT\) (corresponding parts of congruent triangles)
. . . . . . and \(\displaystyle \Delta RST\) is isosceles.
We have reached a contradiction.
Therefore, your original assumption must be incorrect.