indice thing 1

red and white kop!

Junior Member
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Jun 15, 2009
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231
(2^100) - (2^99)
im supposed to be doing pretty advance stuff but this just stumps me
can someone show me how this is done? the answer is to be in the form 2^n
 
Hello, red and white kop!!

Simplify: 2100299\displaystyle \text{Simplify: }\:2^{100} - 2^{99}

The answer is to be in the form 2n\displaystyle 2^n

Factor:   2100299    =    299(21)    =    2991    =    299\displaystyle \text{Factor: }\;2^{100} - 2^{99} \;\;=\;\;2^{99}(2 - 1) \;\;=\;\;2^{99}\cdot 1 \;\;=\;\;2^{99}

 
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