INDEFINITE INTEGRAL

[Ryan Rigdon]

MY PROBLEM

EVALUATE THE INDEFINITE INTEGRAL

integral 4SINX(1+4COSX)^5 DX

U = 1 + 4COSX -DU = 4SINXDX

= INTEGRAL 4SINX(1+COSX)^5 dx = - INTEGRAL U^5 DU = -(U^6)/6 + C

= -1/6 (1+4COSX)^6 + C

gOOD?


HOW DO I PUT IN AN INTEGRAL INSTEAD OF TYPING INTEGRAL. PEACE!!!!!!!!

 

[Deleted member 4993]

MY PROBLEM

EVALUATE THE INDEFINITE INTEGRAL

integral 4SINX(1+4COSX)^5 DX

U = 1 + 4COSX -DU = 4SINXDX

= INTEGRAL 4SINX(1+COSX)^5 dx = - INTEGRAL U^5 DU = -(U^6)/6 + C

= -1/6 (1+4COSX)^6 + C

gOOD?
You should check your answer by differentiating it.

d/dx [-1/6*{1 + 4*cos(x)}[sup:3gcnwi1u]6[/sup:3gcnwi1u] + C]

=-6/6*{1 + 4*cos(x)}[sup:3gcnwi1u]5[/sup:3gcnwi1u]* {-4 * sin(x)}

= 4 * sin(x) * {1 + 4*cos(x)}[sup:3gcnwi1u]5[/sup:3gcnwi1u]

Looks good to me....

HOW DO I PUT IN AN INTEGRAL INSTEAD OF TYPING INTEGRAL. PEACE!!!!!!!!

 

[Ryan Rigdon]

cool. i will remember that thank you.

 

[galactus]

To type an integral sign, try using LaTeX.

\(\displaystyle 4\int\left[sin(x)(1+4cos(x))^{5}\right]dx\)

Click on 'quote' in the upper right hand corner of this ppost to see the code to make it display this way.

 

[Ryan Rigdon]

let me try

\(\displaystyle \int\\)

 

[galactus]

There ya' go. It's easy. A little practice and you'll have it down. There are the basics and the most commonly used ones.

Like \frac{2}{3} for a fraction. In this case, 2/3

If you get good, you can even build charts and diagrams with it.