indefinite integral (Int. by parts) of x^2 e^(x^3) dx

degreeplus

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Oct 7, 2006
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problem: \(\displaystyle \int\limits_{} x^2e^x^3dx\)
I cant figure out how to solve this problem. I need help on the step by step process.

Starting to Solve:
\(\displaystyle \int\limits_{} x^2e^x^3dx\)
I set
u=x^2 dv=e^x^3dx <--- I'm having trouble integrating this is where I get stuck
du=2xdx v=1/3e^x^2
 
Re: indefinite integral (Integration by parts)

degreeplus said:
problem: \(\displaystyle \int\limits_{} x^2e^x^3dx\)
I cant figure out how to solve this problem. I need help on the step by step process.

Starting to Solve:
\(\displaystyle \int\limits_{} x^2e^x^3dx\)
I set
u=x^2 dv=e^x^3dx <--- I'm having trouble integrating this is where I get stuck
du=2xdx v=1/3e^x^2 Does this give dv/dx = e^(x^3)?
Just use u-substitution...
 
why are you using intergration by parts just set u = x^3

du = 3 x^2 dx

which equals

1/3 * intergral e^u

which equals

(e^x^3)/3 + c
 
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