Indefinate Integral

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x

 

[galactus]

$\displaystyle 8\int\frac{1}{z}dz=8ln(z)$

Remember, the derivative of ln(x) is 1/x. Therefore, the antiderivative of 1/x is ln(x).

 

[CatchThis2]

I see how you got that thanks!

 

[lookagain]

$\displaystyle 8\int\frac{1}{z}dz=8ln(z)$

Remember, the derivative of ln(x) is 1/x. Therefore, the antiderivative of 1/x is ln(x).

\(\displaystyle 8 \int \frac{1}{z}dz \ = \ 8 \ln|z| + \bigg C\)