Ryan Rigdon
Junior Member
- Joined
- Jun 10, 2010
- Messages
- 246
I have this problem with this ? cant seem to get the increasing and decreasing part right.
the problem
Determine the intervals where the graph of the given function is increasing, decreasing, concave up and down. Then sketch the graph.
g(x) = 3x^4 - 3x^3 +1
MY WORK.
1. Find f'(x) f'(x) = 12x^3 - 9x^2
2. Set f'(x) = 0 & solve. 12x^3 - 9x^2 = 0 x^(2) (12x-9) = 0 x = 0 x = 3/4
Split points are 0, 3/4 (-infinity, 0) , (0,3/4) , (3/4,infinity)
(-infinity,0) Eval. f'(x) @ x = -1
f'(-1) = -3 y decreasing on (-infinity, 0] by Monotonicity Theorem
(0,3/4) Eval. f'(x) @ x = 1/4
f'(1/4) = 12(1/4)^3 - 9(1/4)^2 = 12(1/64) - 9(1/16) = 12/64 - 36/64 = -24/64 = -3/8
y is decreasing on [0,3/4] by Monotonicity Theorem
(3/4,infinity) Eval. f'(x) @ x = 1
f'(1) = 3 y is increasing on [3/4,infinity) by Monotonicity Theorem
What is wrong with my increasing and decreasing?
the problem
Determine the intervals where the graph of the given function is increasing, decreasing, concave up and down. Then sketch the graph.
g(x) = 3x^4 - 3x^3 +1
MY WORK.
1. Find f'(x) f'(x) = 12x^3 - 9x^2
2. Set f'(x) = 0 & solve. 12x^3 - 9x^2 = 0 x^(2) (12x-9) = 0 x = 0 x = 3/4
Split points are 0, 3/4 (-infinity, 0) , (0,3/4) , (3/4,infinity)
(-infinity,0) Eval. f'(x) @ x = -1
f'(-1) = -3 y decreasing on (-infinity, 0] by Monotonicity Theorem
(0,3/4) Eval. f'(x) @ x = 1/4
f'(1/4) = 12(1/4)^3 - 9(1/4)^2 = 12(1/64) - 9(1/16) = 12/64 - 36/64 = -24/64 = -3/8
y is decreasing on [0,3/4] by Monotonicity Theorem
(3/4,infinity) Eval. f'(x) @ x = 1
f'(1) = 3 y is increasing on [3/4,infinity) by Monotonicity Theorem
What is wrong with my increasing and decreasing?