in the given figure the circles with centre o has chords ab=bc=cd=de . prove that ad=be
S soumili New member Joined Oct 7, 2020 Messages 1 Oct 7, 2020 #1 in the given figure the circles with centre o has chords ab=bc=cd=de . prove that ad=be Attachments download.jpeg 3.8 KB · Views: 1
pka Elite Member Joined Jan 29, 2005 Messages 11,995 Oct 7, 2020 #2 soumili said: in the given figure the circles with centre o has chords ab=bc=cd=de . prove that ad=be Click to expand... Because ab=deab=deab=de we get m(AB^)=m(ED^)m(\widehat{AB})=m(\widehat{ED})m(AB)=m(ED). From which we get m(ABD^)=m(BCE^)m(\widehat{ABD})=m(\widehat{BCE})m(ABD)=m(BCE) Does that imply ab=be ?ab=be~?ab=be ? WHY?
soumili said: in the given figure the circles with centre o has chords ab=bc=cd=de . prove that ad=be Click to expand... Because ab=deab=deab=de we get m(AB^)=m(ED^)m(\widehat{AB})=m(\widehat{ED})m(AB)=m(ED). From which we get m(ABD^)=m(BCE^)m(\widehat{ABD})=m(\widehat{BCE})m(ABD)=m(BCE) Does that imply ab=be ?ab=be~?ab=be ? WHY?
