in the given figure the circles with centre o has chords ab=bc=cd=de . prove that ad=be

[soumili]

in the given figure the circles with centre o has chords ab=bc=cd=de . prove that ad=be

 

[pka]

in the given figure the circles with centre o has chords ab=bc=cd=de . prove that ad=be

Because \(ab=de\) we get \(m(\widehat{AB})=m(\widehat{ED})\).
From which we get \(m(\widehat{ABD})=m(\widehat{BCE})\)
Does that imply \(ab=be~?\) WHY?