implicitly differentiate

[lilgnome57]

What is derivative of the equation with respect to x?
*y^2+(x*y)

 

[tkhunny]

Without the rest of the problem statement, it is very simple:

2xy^2 + y = 0

If we are to assume that y = f(x), this is a different story. You must be well acquainted with the chain rule.

I'll do the easy piece: \(\displaystyle Given \;y=f(x), \;\;\frac{d}{dx}(x\cdot y)\;=\;x\cdot\frac{dy}{dx} + (1)\cdot y\)

You should recognize this piece as an application of the product rule.

 

[Deleted member 4993]

What is derivative of the equation with respect to x?

*y^2+(x*y) <<< Why is there a multiplication symbol(*) without two operand?

 

[mmm4444bot]

derivative of the equation

y^2 + (x*y) This is not an equation.

All equations contain an equal sign.

Kindly proofread and correct your post.

The grouping symbols are not needed.

y^2 + xy

Cheers