lunarskull
New member
- Joined
- Aug 8, 2005
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- 12
assuming that the equations in excersise 14 define x and y implicitily as differentiable functions x=f(t), y=g(t), find the slope of the curve x=f(t), y=g(t) at the given value of t.
14. x=(5-(square root of t))^1/2, y(t-1)=ln y, t=1
plz help
14. x=(5-(square root of t))^1/2, y(t-1)=ln y, t=1
plz help