renegade05
Full Member
- Joined
- Sep 10, 2010
- Messages
- 260
I need some help differentiating the following implicitly defined curve:
\(\displaystyle 2^{(\frac{x}{y})}+2x^2y^3=26\)
My guess is:
\(\displaystyle 2^{(\frac{x}{y})}\ln{2}(y-\frac{x}{y^2}\frac{dy}{dx})+(4xy^3+6x^2y^2\frac{dy}{dx})=0\)
I am pretty sure the the second half (after the first +) of the equation is right, the \(\displaystyle 2^{(\frac{x}{y})}\) is what i am unsure about.
Please help, Thanks!
obvs simplifying is not necessary.
\(\displaystyle 2^{(\frac{x}{y})}+2x^2y^3=26\)
My guess is:
\(\displaystyle 2^{(\frac{x}{y})}\ln{2}(y-\frac{x}{y^2}\frac{dy}{dx})+(4xy^3+6x^2y^2\frac{dy}{dx})=0\)
I am pretty sure the the second half (after the first +) of the equation is right, the \(\displaystyle 2^{(\frac{x}{y})}\) is what i am unsure about.
Please help, Thanks!
obvs simplifying is not necessary.