Implicit Differentiation of an equation - not a funtion

[Keeraaa]

My homework problem (due tomorrow, eep!) says:

"Use implicit differentiation to find y' when (y^2) - y = x."

Whats throwing me for a loop is that the problem then says, "Your final answer will likely contain both x's and y's." When I solve for y' I get:

(2y*y') - y' = 1

which contains no x's! What am I doing wrong??

Thank you for your help!!

 

[daon2]

My homework problem (due tomorrow, eep!) says:

"Use implicit differentiation to find y' when (y^2) - y = x."

Whats throwing me for a loop is that the problem then says, "Your final answer will likely contain both x's and y's." When I solve for y' I get:

(2y*y') - y' = 1

which contains no x's! What am I doing wrong??

Thank you for your help!!

First, you didn;t solve for y' yet, right? Second, what your teacher said is a general statement for these kinds of problems, as it can happen. She said "likely" but probably should have said "might."

I agree with what you have so far.

 

[Keeraaa]

First, you didn;t solve for y' yet, right? Second, what your teacher said is a general statement for these kinds of problems, as it can happen. She said "likely" but probably should have said "might."

I agree with what you have so far.

I did solve, sorry: y' = 1/(2y-1)

If that's what you get as well, then I feel better. My math teacher writes all the problems himself, and he has never thrown us for a loop before. When he says "the answer will likely contain x's & y's," it means it will definitely contain x's & y's. So I guess I just feel like I came up with the wrong answer.

Either way, thanks for your help!