What is wrong with my work?
The problem is:\(\displaystyle \L \;\frac{14\,-\,2i}{3\,+\,i}\)
\(\displaystyle \L \;\frac{14\,-\,2i}{3\,+\,i}\,\cdot\,\frac{3\,-\,i}{3\,-\,i}\,=\,\frac{42\,-\,14i\,-\,6i\,+\,2{i}^2}{9\,-\,{i}^2\)
\(\displaystyle \L \;\frac{2{i}^2\,-\,20i\,+\,42}{9\,-\,{i}^2\)
\(\displaystyle \L \;\frac{2(\,-\,1)\,-\,20i\,+\,42}{9\,-\,(-1)}\)
\(\displaystyle \L \;\frac{40\,-\,20i}{10}\,=\,4\,-\,2i\)
The problem is:\(\displaystyle \L \;\frac{14\,-\,2i}{3\,+\,i}\)
\(\displaystyle \L \;\frac{14\,-\,2i}{3\,+\,i}\,\cdot\,\frac{3\,-\,i}{3\,-\,i}\,=\,\frac{42\,-\,14i\,-\,6i\,+\,2{i}^2}{9\,-\,{i}^2\)
\(\displaystyle \L \;\frac{2{i}^2\,-\,20i\,+\,42}{9\,-\,{i}^2\)
\(\displaystyle \L \;\frac{2(\,-\,1)\,-\,20i\,+\,42}{9\,-\,(-1)}\)
\(\displaystyle \L \;\frac{40\,-\,20i}{10}\,=\,4\,-\,2i\)