Imaginary Number i

[dagr8est]

If a and b are real numbers, i^2=-1, and (a+b)+5i=9+ai, what is the value of b?

a)4
b)5
c)9
d)4+5i
e)5+4i

This looks simple enough but I can't figure out how to get rid of the a.

 

[pka]

Look at this: (a+b)+5i=9+ai.
So if a=5, what is b?

 

[dagr8est]

Aw man, I cannot believe I didn't see that. I was wondering why brackets were included. Thanks, that makes it so easy now.