Imaginary/Complex Numbers as zeroes of a polynomial

aube0008

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Jan 10, 2007
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Hi the problem I am figuring out is to find an equation where the beginning constant is 1 and the zeros are 3i and 2-i. I originally set it up as (x-3i)(x+3i)((x-(2-i))(x-(2+i)) and solved and got x^4 - 4x^3 + 14x^2 - 36x + 45, is this the correct way to set it up and the correct answer? Thanks!
 
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