Here is the problem: 7=10-g/-2 how do I solve for g?
B biker2 New member Joined Sep 18, 2016 Messages 1 Sep 18, 2016 #1 Here is the problem: 7=10-g/-2 how do I solve for g?
D Deleted member 4993 Guest Sep 19, 2016 #2 biker2 said: Here is the problem: 7=10-g/-2 how do I solve for g? Click to expand... Is your problem: \(\displaystyle 7 \ = \ 10 \ - \ \dfrac{g}{-2} \) or \(\displaystyle 7 \ = \ \dfrac{10 - g}{-2} \)
biker2 said: Here is the problem: 7=10-g/-2 how do I solve for g? Click to expand... Is your problem: \(\displaystyle 7 \ = \ 10 \ - \ \dfrac{g}{-2} \) or \(\displaystyle 7 \ = \ \dfrac{10 - g}{-2} \)
S soroban Elite Member Joined Jan 28, 2005 Messages 5,586 Sep 19, 2016 #3 biker2 said: \(\displaystyle \text{Here is the problem: }\;7\:=\:\dfrac{10-g}{-2}\quad \text{How do I solve for }g?\) Click to expand... \(\displaystyle \begin{array}{cccccc} \text{Multiply by }-2: & -2(7) &=& -2\left(\dfrac{10-g}{-2}\right) \\ \\ & -14 &=& 10-g \\ \\ \text{Add }g: &-14 + g&=& 10-g+g \\ \\ & -14 + g & =& 10 \\ \\ \text{Add 14: } & -14 + g +14 &=& 10 + 14 \\ \\ & g &=& 24 \end{array}\)
biker2 said: \(\displaystyle \text{Here is the problem: }\;7\:=\:\dfrac{10-g}{-2}\quad \text{How do I solve for }g?\) Click to expand... \(\displaystyle \begin{array}{cccccc} \text{Multiply by }-2: & -2(7) &=& -2\left(\dfrac{10-g}{-2}\right) \\ \\ & -14 &=& 10-g \\ \\ \text{Add }g: &-14 + g&=& 10-g+g \\ \\ & -14 + g & =& 10 \\ \\ \text{Add 14: } & -14 + g +14 &=& 10 + 14 \\ \\ & g &=& 24 \end{array}\)
