If y = x^3 / 3^x, find y'. my work: Y' = ln 3x^2- (ln 3) 3^x
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Re: If y = x^3 / 3^x, find y'. I get x^2(x - x(ln3) / 3^x
Note: The Product Rule states that, for two differentiable functions g(x) and h(x), with f(x) = g(x)h(x), the derivative of this product is given by the rule f'(x) = g'(x)h(x) + g(x)h'(x). I'm not sure what you mean by your "Product Rule"...? :shock:
Please reply with clarification. Thank you!
Eliz.
How does Y relate to the original y and the required derivative y'?venialove said:
Note: The Product Rule states that, for two differentiable functions g(x) and h(x), with f(x) = g(x)h(x), the derivative of this product is given by the rule f'(x) = g'(x)h(x) + g(x)h'(x). I'm not sure what you mean by your "Product Rule"...? :shock:
Please reply with clarification. Thank you!
Eliz.