If x-p is factor of mx^2+nx+q, show that -2 sqrt(mq) <= n <=2 sqrt(mq)

[Gehan]

Hi, i'm trying to solve this question, but I can't, can anyone help please:

If (x − p) is a factor of mx² + nx + q, show that −2* square root of (mq) ≤ n ≤ 2*square root of (mq)

Thank you :roll:

 

[Deleted member 4993]

Hi, i'm trying to solve this question, but I can't, can anyone help please:


If (x − p) is a factor of mx + nx + q, show that −2* square root of (mq) ≤ n ≤ 2*square root of (mq)

Thank you :roll:

Have you posted the problem correctly?

Are you sure the function is not mx2 + nx + q

If it is then you need to show that

m*q = n²/4

What are your thoughts?

Please share your work with us ...even if you know it is wrong

If you are stuck at the beginning tell us and we'll start with the definitions.

You need to read the rules of this forum. Please read the post titled "Read before Posting" at the following URL:

http://www.freemathhelp.com/forum/th...Before-Posting

 

[Ishuda]

Hi, i'm trying to solve this question, but I can't, can anyone help please:


If (x − p) is a factor of mx + nx + q, show that −2* square root of (mq) ≤ n ≤ 2*square root of (mq)

Thank you :roll:

Even if we assume the problem is "If (x-p) is a factor of mx²+nx+q ...", the rest of the problem can't be stated correctly if I am understanding it correctly [let m=1, n=-3, q=2]

 

[Gehan]

yes it is mx2, I used copy and paste, sorry

 

[Gehan]

the rest of the problem is : show that:

1. −2 (mq)1/2 ≤ n ≤ 2 (mq)1/2.
   
   mq is to the power 1/2 i.e square root of mq
   

 

[Deleted member 4993]

the rest of the problem is : show that:

2. −2 (mq)1/2 ≤ n ≤ 2 (mq)1/2.
   
   mq is to the power 1/2 i.e square root of mq

Now you show your work!!

What do you know about quadratic equations?

What do you know about "remainder theorem"?

How can those be applied here?

Also look at Ishuda's post - how do you resolve that?

 

[Gehan]

if (x-p) is a factor , the remainder is zero