BeccaSMill
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if x/2x-7 is a fraction, find the smallest integral value of x so that the numerator is less than the denominator
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If x/2x-7 is a fraction, find smallest integer x so num. < denom.
- Thread starter BeccaSMill
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Is the expression meant to be x/(2x - 7), so the seven is included in the denominator? What inequality have you set up, using the numerator's expression and the denominator's expression? How far have you gotten in solving that linear inequality?
Please be complete. Thank you!
HallsofIvy
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1) What is the numerator?
2) What is the denominator?
3) "the numerator is less than the denominator" is numerator< denominator. Put your responses to (1) and (2) into that and solve the inequality to find the "solution set", the set of all values of x that satisfy the inequality. Pick the smallest integer in that set.
2) What is the denominator?
3) "the numerator is less than the denominator" is numerator< denominator. Put your responses to (1) and (2) into that and solve the inequality to find the "solution set", the set of all values of x that satisfy the inequality. Pick the smallest integer in that set.