If x > 2, then x2 – x – 6/x2 – 4 =...?

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jjamesdk

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If x > 2, then x2 – x – 6/x2 – 4 =...?

Hey all, I've got this problem trying to study for upcoming test, I have no idea where to begin to solve it, can anyone help? Thanks

If x > 2, then x2 – x – 6/x2 – 4 =

A. x – 3/2
B. x – 3/x – 2
C. x – 3/x + 2
D. 3/2

( sorry, posted in wrong section, my bad )
 
jjamesdk said:
If x > 2, then x2 – x – 6/x2 – 4 =
Click to expand...
As posted, what follows the "then" above (assuming the numbers after the letters are powers on variables) means the following:

. . . . .\(\displaystyle x^2\, -\, x\, -\, \dfrac{6}{x^2}\, -\, 4\)

Is this what you meant? Or did you maybe mean to say "(x^2 - x - 6)/(x^2 - 4)" which means the below?

. . . . .\(\displaystyle \dfrac{x^2\, -\, x\, -\, 6}{x^2\, -\, 4}\)

In either case, what have you tried? How far did you get? Where are you stuck? You say that you "have no idea", but this suggests that you missed a week or so of class. Are you needing lesson links so you can first study the topic?

Thank you. ;)
 
Need help basic Algebra

stapel said:
As posted, what follows the "then" above (assuming the numbers after the letters are powers on variables) means the following:

. . . . .\(\displaystyle x^2\, -\, x\, -\, \dfrac{6}{x^2}\, -\, 4\)

Is this what you meant? Or did you maybe mean to say "(x^2 - x - 6)/(x^2 - 4)" which means the below?

. . . . .\(\displaystyle \dfrac{x^2\, -\, x\, -\, 6}{x^2\, -\, 4}\)

In either case, what have you tried? How far did you get? Where are you stuck? You say that you "have no idea", but this suggests that you missed a week or so of class. Are you needing lesson links so you can first study the topic?

Thank you. ;)
Click to expand...

Hey thanks for the reply. I actually haven't been to school in 9 years, I'm self-studying for a placement test at the local community college. And any links to lessons for this topic would be appreciated.

.\(\displaystyle \dfrac{x^2\, -\, x\, -\, 6}{x^2\, -\, 4}\) is what I meant. It's been years since I've done algebra, all I'm asking for is a helping hand in the right direction, thank you.
 
jjamesdk said:
Hey thanks for the reply. I actually haven't been to school in 9 years, I'm self-studying for a placement test at the local community college. And any links to lessons for this topic would be appreciated.

.\(\displaystyle \dfrac{x^2\, -\, x\, -\, 6}{x^2\, -\, 4}\) is what I meant. It's been years since I've done algebra, all I'm asking for is a helping hand in the right direction, thank you.
Click to expand...

Hint: factorize the numerator and the denominator. Both are quadratic expressions.
 
jjamesdk said:
Hey thanks for the reply. I actually haven't been to school in 9 years, I'm self-studying for a placement test at the local community college. And any links to lessons for this topic would be appreciated.
Click to expand...
Here is one set of links. https://www.khanacademy.org/math/algebra

A piece of advice that is well intended. It is fine to review in preparation for a placement test material that you once grasped firmly; you are just trying to reactivate what you already learned. But many people try to skip ahead in a placement test. That is a recipe for disaster because then you get into an advanced class and find you are not really ready for it.
 
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