If cone radius tripled, how many times larger is volume?

Re: Radius? Volume? HELP!!!

Hello, DestinyLazaro!

If the radius of a cone is tripled, the volume of the cone is how many times larger?

The volume of the original cone is: V1  =  13πr2h\displaystyle \text{The volume of the original cone is: }\:V_1 \;=\;\tfrac{1}{3}\pi r^2h

If the radius is tripled to 3r, then: V2=13π(3r)2h=3πr2h\displaystyle \text{If the radius is tripled to }3r\text{, then: }\:V_2 \:=\:\tfrac{1}{3}\pi (3r)^2h \:=\:3\pi r^2h

We have: V2V1=3πr2h13πr2h=9\displaystyle \text{We have: }\:\frac{V_2}{V_1} \:=\:\frac{3\pi r^2h}{\frac{1}{3}\pi r^2h} \:=\:9

Therefore, the new cone is 9 times larger.

 
Re: Radius? Volume? HELP!!!

Remember that the ratio of the volumes is the cube of the scale factor, i.e. the ratio of two corresponding lengths.
 
Top