If (5a-3b) / a = (4a+b-2c) / (a+4b-2c) = (a+2b-3c) / (4a-4c) then prove 6a = 4b = 3c.

[saibal]

If (5a-3b) / a = (4a+b-2c) / (a+4b-2c) = (a+2b-3c) / (4a-4c) then prove 6a = 4b = 3c.

 

[Deleted member 4993]

If (5a-3b) / a = (4a+b-2c) / (a+4b-2c) = (a+2b-3c) / (4a-4c) then prove 6a = 4b = 3c.

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[saibal]

prealgebra

I am trying to equate the given proportions to 1/2. But fails to do so.

 

[saibal]

Pre algebra

I GOT IT. Sorry to bother you.
For (2), (5a-3b)/a=-(4a+b-2c)/-(a+4b-2c)=(a+2b-3c... [multiplying by -1 both num. and deno. of 2nd ratio] and now by addendo, we get each ratio = (2a-2b-c)/(4a-4b-2c) = 1/2. The rest is easy.