i want to show the sum of odd is zero

logistic_guy

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here is the question

Show that if x[n]\displaystyle x[n] is an odd signal, then n=x[n]=0\displaystyle \sum_{n=-\infty}^{\infty} x[n] = 0.

is it correct to say if x[n]=n3\displaystyle x[n] = n^3 then the partial sum is n=11x[n]=n=11n3=1+0+1=0\displaystyle \sum_{n=-1}^{1} x[n] = \sum_{n=-1}^{1} n^3 = -1 + 0 + 1 = 0 then n=n3=0\displaystyle \sum_{n=-\infty}^{\infty} n^3 = 0
 
here is the question

Show that if x[n]\displaystyle x[n] is an odd signal, then n=x[n]=0\displaystyle \sum_{n=-\infty}^{\infty} x[n] = 0.

is it correct to say if x[n]=n3\displaystyle x[n] = n^3 then the partial sum is n=11x[n]=n=11n3=1+0+1=0\displaystyle \sum_{n=-1}^{1} x[n] = \sum_{n=-1}^{1} n^3 = -1 + 0 + 1 = 0 then n=n3=0\displaystyle \sum_{n=-\infty}^{\infty} n^3 = 0
I would rearrange the sum into a sum of pairs, each of which is 0 by definition.
 
here is the question

Show that if x[n]\displaystyle x[n] is an odd signal, then n=x[n]=0\displaystyle \sum_{n=-\infty}^{\infty} x[n] = 0.

is it correct to say if x[n]=n3\displaystyle x[n] = n^3 then the partial sum is n=11x[n]=n=11n3=1+0+1=0\displaystyle \sum_{n=-1}^{1} x[n] = \sum_{n=-1}^{1} n^3 = -1 + 0 + 1 = 0 then n=n3=0\displaystyle \sum_{n=-\infty}^{\infty} n^3 = 0
One example is not a proof; but with some extra words, this example could be used to "show" (informally) why it generalizes to any odd function and infinitely many terms (assuming convergence).

In other words, what @lev888 said!
 
assuming convergence
Depends on how we define \sum_{-\infty}^\infty, doesn't it? I.e., if =limkkk\sum_{-\infty}^\infty = \lim_{k\rightarrow\infty} \sum_{-k}^k then we don't depend on convergence of odd signals/sequences.
 
One can use generalized function of Scharwz theory. Int of comb (x)*x will be the integation of odd function on symmetric interval. That is 0.
Comb is or cha(x) is a sum of Dirac's distributions
 
thank you guys

is it correct to write this notation?

n=x[n]=n=n3=....+(n)3+....+(5)3+....+03+....+53+....+n3+....=....+(5353)+....+(n3n3)+....=0\displaystyle \sum_{n=-\infty}^{\infty} x[n] = \sum_{n=-\infty}^{\infty} n^3 = .... + (-n)^3 + .... + (-5)^3 + .... + 0^3 + .... + 5^3 + .... + n^3 + .... = .... + (5^3 - 5^3) + .... + (n^3 - n^3) + .... = 0

maybe i can do this

n=x[n]=......+x[n]+.......+x[0]+........+x[n]+........=.....+(x[n]+x[n])+.......=0\displaystyle \sum_{n=-\infty}^{\infty} x[n] = ...... + x[-n] + ....... + x[0] + ........ + x[n] + ........ = ..... + (x[-n] + x[n]) + ....... = 0

One can use generalized function of Scharwz theory. Int of comb (x)*x will be the integation of odd function on symmetric interval. That is 0.
Comb is or cha(x) is a sum of Dirac's distributions
when i answer this question correctly, write your full solution. you can now write some of it with mathematics notation
 
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