logistic_guy
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- Joined
- Apr 17, 2024
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- 287
here is the question
Show that if \(\displaystyle x[n]\) is an odd signal, then \(\displaystyle \sum_{n=-\infty}^{\infty} x[n] = 0\).
is it correct to say if \(\displaystyle x[n] = n^3\) then the partial sum is \(\displaystyle \sum_{n=-1}^{1} x[n] = \sum_{n=-1}^{1} n^3 = -1 + 0 + 1 = 0\) then \(\displaystyle \sum_{n=-\infty}^{\infty} n^3 = 0\)
Show that if \(\displaystyle x[n]\) is an odd signal, then \(\displaystyle \sum_{n=-\infty}^{\infty} x[n] = 0\).
is it correct to say if \(\displaystyle x[n] = n^3\) then the partial sum is \(\displaystyle \sum_{n=-1}^{1} x[n] = \sum_{n=-1}^{1} n^3 = -1 + 0 + 1 = 0\) then \(\displaystyle \sum_{n=-\infty}^{\infty} n^3 = 0\)