i need to find the equation to a line...help a.s.a.p.

S

sportsaholic2397

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Jun 12, 2009
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Find equation of the line that passes through points (7,3) and (2,9)

I Have an answer but unsure of whether it is right...

my answer:

y= -6/9 x - 69/9

someone please let me know if that is correct...
 
Give it another go.

The slope is \(\displaystyle \frac{9-3}{2-7}=\frac{-6}{5}\)

Should be \(\displaystyle y=\frac{-6}{5}x+\frac{57}{5}\)
 
That's not what I get. What equation(s) did you use? Show what you did so we can spot your error.
 
so it is suppose to be a -2....

and i started by doing the y2-y1/x2-x1 and so i had 9-3/-2-7 which gives me -6/9... and then from that i did the m= y-y1/x-x1 which was -6/9 = y-3/x-7.
Cross multiply, and get 6x-42=-9y+27. then do the addition or subtraction and then finish with division to get my y intercept and get a final answer of y=-6/9 x - 69/9
 


Hello sportsaholic2397:

Your work is okay, except that we generally reduce ratios to lowest terms (as soon as possible).

m = -6/9 = -2/3

If you do this before cross-multiplying, then your y-intercept of 69/9 will also end up reduced.

Cheers,

~ Mark

 
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