multiply (2y + 1)(3y to the second power minus 2y + 3)
E ERIK VARGAS New member Joined Feb 8, 2006 Messages 6 Feb 8, 2006 #1 multiply (2y + 1)(3y to the second power minus 2y + 3)
T trist666 New member Joined Feb 7, 2006 Messages 14 Feb 8, 2006 #2 multiply (2y + 1)(3y to the second power minus 2y + 3) (2y+1)(3y^2-2y+3) --->6y^3-4y^2+6y+3y^2-2y+3) --->6y^3-y^2+4y+3 NB: 6y^3 is 6y to the power of 3
multiply (2y + 1)(3y to the second power minus 2y + 3) (2y+1)(3y^2-2y+3) --->6y^3-4y^2+6y+3y^2-2y+3) --->6y^3-y^2+4y+3 NB: 6y^3 is 6y to the power of 3
E ERIK VARGAS New member Joined Feb 8, 2006 Messages 6 Feb 9, 2006 #3 trist666 said: multiply (2y + 1)(3y to the second power minus 2y + 3) (2y+1)(3y^2-2y+3) --->6y^3-4y^2+6y+3y^2-2y+3) --->6y^3-y^2+4y+3 NB: 6y^3 is 6y to the power of 3 Click to expand... thank u
trist666 said: multiply (2y + 1)(3y to the second power minus 2y + 3) (2y+1)(3y^2-2y+3) --->6y^3-4y^2+6y+3y^2-2y+3) --->6y^3-y^2+4y+3 NB: 6y^3 is 6y to the power of 3 Click to expand... thank u
