Anonymous5
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- Jul 19, 2022
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The question is 8x squared - 27y squared ÷ (2x-3y) .Sorry ,I don't know how to type indices. The book says what the answer is but I don't know how to do this.
Please make sure that you have posted the correct problem. You said:The question is 8x squared - 27y squared ÷ (2x-3y) .Sorry ,I don't know how to type indices. The book says what the answer is but I don't know how to do this.
If you want to type "x squared" you can do this by typing x^2. Of course, as Mr Khan says you need to be careful with parenthesis.The question is 8x squared - 27y squared ÷ (2x-3y) .Sorry ,I don't know how to type indices. The book says what the answer is but I don't know how to do this.
The question is 8x squared - 27y squared ÷ (2x-3y) .Sorry ,I don't know how to type indices. The book says what the answer is but I don't know how to do this.
(8x cubed - 27y cubed) ÷ (2x - 3y) → \(\displaystyle \frac{8x^3 - 27y^3}{2x - 3y}\) = ?
Correct and subsequently editedAdditional grouping symbols would have to be added above as shown for this to be true.